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引用 | 編輯
kyahm
2008-11-30 15:28 |
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x0
想請各位大大幫幫忙, 感激不盡.... 題目如下... 通用以下程式改寫發10張牌,將其所有點數相加printf出來.... 重點:洗牌, 發10張牌, 點數相加...(*要用C寫喔. 謝謝~*) #include<stdio.h> #include<stdlib.h> #include<time.h> void shuffle(int wdeck[]); void deal(const int wdeck[],const char *wface[], const char *wsuit[]); int main () { const char *suit={"H","D","C","S"}; const char *face={"ace","deuce","three","four","five","six", .. 訪客只能看到部份內容，免費 加入會員  x0
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引用 | 編輯
teldeanmac85
2008-12-02 01:25 |
1樓
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複製程式
#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#define N 52
int main(int argc, char* argv[])
{
int poker[N], sum = 0;
int i, j, tmp, remain;
// 初始化陣列
for(i = 0; i < N; i++){
poker[i] = i;
}
srand(time(0));
// 洗牌
for(i=0;i<N;i++){
j = rand() % N ;
tmp = poker[i];
poker[i] = poker[j];
poker[j] = tmp;
}
for(i = 0; i < 10; i++) {
// 判斷花色
switch((poker[i] / 13)) {
case 0: printf("H"); break;
case 1: printf("D"); break;
case 2: printf("C"); break;
case 3: printf("S"); break;
}
// 撲克牌數字
remain = (poker[i] % 13)+1;
//點數相加
sum = sum + remain;
switch(remain) {
case 13: printf("K "); break;
case 12: printf("Q "); break;
case 11: printf("J "); break;
default: printf("%d ", remain); break;
}
}
printf("\n");
printf("SUM : %d\n",sum);
return 0;
}////////////////////////////////////// C6 D8 H6 DQ C1 D4 CJ D7 C2 SJ SUM : 68 ////////////////////////////////////// 作法 : 52張牌 填進 poker[52] = 0~51 poker / 13 => row (poker % 13) +1 => col (必須+1 shift 1~52) x0
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