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sakashan
2006-04-16 15:46 |
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![]() cout << (a<<2) <<"\n"; //___156____ cout << ~a <<"\n"; //___-40____ cout << ~(a ^ b) <<"\n"; //___-59____ a=31000;b=23001;a+=b;cout<<a<<”\n”; //__-11535_____ a=-32768;a-=1;cout <<a << endl; //__32767_____ 11. int a=5; cout << a .. 访客只能看到部份内容,免费 加入会员 ![]()
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dxman
2006-04-18 12:43 |
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刚刚看了一下..大概知道一些..小弟刚学不是很懂..
有不对的地方请多多指导~~ 9. short int a = 39,b = 29; //将a,b定义为short int的资料型态..范围-32768~32767 cout << (a<<2) <<"\n"; //将a=39左移两各位元(00100111==>10011100) cout << ~a <<"\n"; //将a作补数运算.. ~39 = -40.. ~0 = -1 cout << ~(a ^ b) <<"\n"; //a^b==>将a跟b作XOR运算{00100111(39) XOR 00011101(29)} // =00111010(58) 再作补数运算 ~58 = -59 a=31000;b=23001;a+=b;cout<<a<<”\n”; //32767+1=-32768...因为超出short int定义的范围 //所以a+b会变成54001==>-11535 a=-32768;a-=1;cout <<a << endl; //这各就跟上一各同意思 -32768+1=32767 ![]() |